A simple pendulum rotates in a horizontal plane with an angular velocity ω ω about a fixed point P in gravity -free space. There is a negative charge at P. The bob gradually emit photo electrons (Leave the energy and momentum of incident photons and emitted electrons). The total force acting on the bob is T.
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(c, d): As no forces act on the system, ω ω remains constant. Hence, T = m l ω ω 2 remains constant. However, T is the sum of electrostatic force of attraction on the bob and the force exerted by the string due to elastic strain in it. As the positive charge on the bob increases due to photoemission, the electrostatic force on it increases, and the elastic strain on the string must decrease.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems